KMnO₄ reacts with oxalic acid according to the equation, 2MnO₄^- + 5C₂O₄^2- + 16H^+ → 2Mn^+ + CO₂ + H₂O, here 20 ml of 0.1 M KMnO₄ is equivalent to [CBSE PMT 1996]

Question: KMnO reacts with oxalic acid according to the equation, 2MnO^- + 5CO^2- + 16H^+ → 2Mn^+ + CO₂ + HO, here 20 ml of 0.1 M KMnO is equivalent to [CBSE PMT 1996]

(a) 20 ml of 0.5 M HCO

(b) 50 ml of 0.1 M HCO

(c) 50 ml of 0.5 M H₂CO

(d) 20 ml of 0.1 M HCO


Correct Answer: (b) 50 ml of 0.1 M HCO


Question: KMnO₄ reacts with oxalic acid according to the equation, 2MnO₄^- + 5C₂O₄^2- + 16H^+ → 2Mn^+ + CO₂ + H₂O, here 20 ml of 0.1 M KMnO₄ is equivalent to [CBSE PMT 1996] (a) 20 ml of 0.5 M H₂C₂O₄ (b) 50 ml of 0.1 M H₂C₂O₄ (c) 50 ml of 0.5 M H₂C₂O₄ (d) 20 ml of 0.1 M H₂C₂O₄


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