Question: The number of atoms in 4.25 g of NH₃ is approximately [CBSE PMT 1999; MH CET 2003]
(a) 1 x 10²³
(b) 2 x 10²³
(c) 4 x 10²³
(d) 6 x 10²³
Correct Answer: (d) 6 x 10²³
![Question: The number of atoms in 4.25 g of NH₃ is approximately [CBSE PMT 1999; MH CET 2003] (a) 1 x 10²³ (b) 2 x 10²³ (c) 4 x 10²³ (d) 6 x 10²³](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhtJs2Lugo22Uyj2xPOwvskVxRH-qf1TKD6tPqDXV9JRRvBhhNWGaz2M_F0gRLPDXeaDWurCxf3X5x6-Iiy85KyXl2dARyNKQuVD3B4OreBXtSSTNZd5e2WZ2XWFrZLriVOmRU9BJg9PcdFAqIsPCGuMp2tlEo2hrVaCL_FZ_yBBylE7-ntgNVTrb0T/s1920/The%20number%20of%20atoms%20in%204.25%20g%20of%20NH%E2%82%83%20is%20approximately%20%5BCBSE%20PMT%201999;%20MH%20CET%202003%5D.jpg "Question: The number of atoms in 4.25 g of NH₃ is approximately [CBSE PMT 1999; MH CET 2003] (a) 1 x 10²³ (b) 2 x 10²³ (c) 4 x 10²³ (d) 6 x 10²³")
The number of atoms in 4.25 g of NH₃ is approximately [CBSE PMT 1999; MH CET 2003]