What should be the weight and moles of AgCl precipitate obtained on adding 500ml of 0.20 M HCl in 30 g of AgNO₃ solution? ( AgNO₃ = 170)

Question: What should be the weight and moles of AgCl precipitate obtained on adding 500ml of 0.20 M HCl in 30 g of AgNO₃ solution? ( AgNO₃ = 170)

(a) 14.35 g

(b) 15 g

(c) 18 g

(d) 19 g

Correct Answer: (a) 14.35 g

Question: What should be the weight and moles of AgCl precipitate obtained on adding 500ml of 0.20 M HCl in 30 g of AgNO₃ solution? ( AgNO₃ = 170) (a) 14.35 g (b) 15 g (c) 18 g (d) 19 g

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